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(6x^2+9x+9)-(5x^2+3x-7)=0
We get rid of parentheses
6x^2-5x^2+9x-3x+9+7=0
We add all the numbers together, and all the variables
x^2+6x+16=0
a = 1; b = 6; c = +16;
Δ = b2-4ac
Δ = 62-4·1·16
Δ = -28
Delta is less than zero, so there is no solution for the equation
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